Correct Answer:- 20

Explanation:- Let Barun’s age be 10x. Arun’s age is 4x. The difference of these ages in 6x, a constant. When Arun’s age is 50% of Barun’s age, this difference also would be 50% ie Barun’s age, at that stage would be 12x. It would be increase by 20%.

we can see that,

On Day 1, the person works alone. So, work done on Day 1 = 1/120

Next day, another person joins him, Work done on Day 2 = 2/120

And so on, until the final day

So, sum total of work done = 1/120 + 2/120 +………+ n/120 = 1

(1/120) (1 + 2+3+……+n) = 1

(1/120) [n(n+1)/2] = 1 (Sum of n positive integers)

On solving, we get n = 15.

we can see that,

53 + …….. + 57 = 630

Remaining sum of weights = 630 – 53 – 57 = 520

Now, the minimum weight can be 53. So, to find maximum number of people

N(max) = 520/53 = 9.81

So, maximum number of people possible = 9+2 = 11

Answer: 11

we can see that,

Speed in first case: s

Speed in second case: s’ = 5s/4

We know that, time is inversely proportional with speed

Therefore, the time would be 4/5 times the time, i.e., 1/5 less. This one fifth is 20 min. Therefore, the time taken in the first case is 100 min.

The distance = 12*(5/3) = 20 km

Answer: 2

we can assume that,

Total amount of savings as ‘s’

Amount kept in FD = 0.5s

Savings left = 0.5s

Amount kept in stocks = (0.3) * (0.5) * s = 0.15s

Amount kept in Bank Account = (0.7) * (0.5) * s = 0.35s

Amount deposited in the bank = 0.5s + 0.35s = 0.85s = 59500. So, s = 70000.

Answer: 70000

**Verbal Ability : | Q.01- Q.06 | Q.07- Q.12 | Q.13- Q.18 | Q.19- Q.21 | Q.22- Q.24 | Q.25- Q.29 | Q.30 – Q.34 |**

**Logical Reasoning : | Q.01- Q.04 | Q.05- Q.08 | Q.09- Q.12 | Q.13- Q.16 | Q.17- Q.20 | Q.21- Q.24 | Q.25 – Q.28 | Q.29 – Q.32 |**

**Quantitative Aptitude: | Q.01- Q.05 | Q.06- Q.10 | Q.11- Q.15 | Q.16- Q.20 | Q.21- Q.25 | Q.26- Q.30 | Q.31 – Q.34 |**

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