We get 4 cases
CASE – 1
a+3 = 3b
a-1 = 2b-2
CASE – 2
a+3 = 3b
a-1 = 2b + 2
CASE – 3
a+3 = -3b
a-1 = 2b-2
CASE – 4
a+3 = -3b
a-1 = -2b+2
Subtracting the second equation from the first we get,
Case 1: 4 = b+2 => b = 2, a = 3 (Rejected as a and b should be of opposite sign)
Case 2: 4 = b-2 => b = 6, a = 15 (Rejected as a and b should be of opposite sign)
Case 3: 4 = -5b+2 => b = -2/5 (Rejected as both a and b are integers)
Case 4: 4 = -b-2 => b = -6, a = 15 (Accepted)
So, a^2/b^2 = (15/6)^2 = 25/4
Option (D)