We get 4 cases

CASE – 1

a+3 = 3b

a-1 = 2b-2

CASE – 2

a+3 = 3b

a-1 = 2b + 2

CASE – 3

a+3 = -3b

a-1 = 2b-2

CASE – 4

a+3 = -3b

a-1 = -2b+2

Subtracting the second equation from the first we get,

Case 1: 4 = b+2 => b = 2, a = 3 (Rejected as a and b should be of opposite sign)

Case 2: 4 = b-2 => b = 6, a = 15 (Rejected as a and b should be of opposite sign)

Case 3: 4 = -5b+2 => b = -2/5 (Rejected as both a and b are integers)

Case 4: 4 = -b-2 => b = -6, a = 15 (Accepted)

So, a^2/b^2 = (15/6)^2 = 25/4

Option (D)