Q1: Option (B)

Q2: Option (C)

Q3: Option (B)

Q4: Option (A)

Solutions

Q1 With the original table given in the question 0.375*800 – (0.6+0.55)*120 = 162¬ Option (B)

Q2 With the original table given in the question 0.52*800-0.3*120-0.65*560 = 16 Option (C)

Q3 With the original table given in the question 120*((0.55-0.3/2) – (0.45-0.3/2)) = 120*(0.4-0.3) = 12 Option (B)

Q4 Cost of normal cheese pizza = 3/5th of (500 + 50) = 330 Number of normal cheese pizzas from Q2 = 16 From the remaining 120 – 16 = 104 pizzas, 0.6*120 – 25% of 16 = 60 are thin crust and the remaining 44 are Deep dish Total cost = 60*500 + 44*550 + 16*330 = 59480 Option (A)