Six people U, V, W, X, Y, and Z, are standing at different intersections. No two people are standing at the same intersection.

The following additional facts are known.

1. X, U, and Z are standing at the three corners of a triangle formed by three street segments.

2. X can see only U and Z.

3. Y can see only U and W.

4. U sees V standing in the next intersection behind Z.

5. W cannot see V or Z.

6. No one among the six is standing at intersection d.

Q. 1: Who is standing at intersection a?

1. V

2. W

3. No one

4. Y

1. U and Z only

2. Z only

3. U only

4. U, W and Z only

Q. 3: What is the minimum number of street segments that X must cross to reach Y?

1. 1

2. 2

3. 3

4. 4

Q. 4: Should a new person stand at intersection d, who among the six would she see?

1. W and X only

2. U and W only

3. V and X only

4. U and Z only

1. Option: 3

2. Option: 1

3. Option: 2

4. Option: 1

**Explanation (1 to 4):**

X,U,Z are at ends of a triangle so they can be at any of b,c,f,g intersections.

Now X cannot be at g since he sees only 2 people.

UZV have to be in a straight line and x sees only U and z thus

X must be at b, V at e, Z at f, U at g.

Since Y can see W and W cannot see either V or Z thus

Y must be at k and W must be at at l.

– V –

X Z –

– U Y

– – W

Now all questions can be answered.

**Verbal Ability : | Q.01- Q.05 | Q.06- Q.10 | Q.11- Q.15 | Q.16- Q.20 | Q.21- Q.24 | Q.25- Q.29 | Q.30 – Q.34 |**

**Logical Reasoning : | Q.01- Q.04 | Q.05- Q.08 | Q.09- Q.12 | Q.13- Q.16 | Q.17- Q.20 | Q.21- Q.24 | Q.25 – Q.28 | Q.29 – Q.32 |**

**Quantitative Aptitude: | Q.01- Q.05 | Q.06- Q.10 | Q.11- Q.15 | Q.16- Q.20 | Q.21- Q.25 | Q.26- Q.30 | Q.31 – Q.34 |**

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