dimension of rectangle with ends of diagonal being(1,1) and (4,6) = 3*5

thus number of paths from (1,1) to (4,6) = (5+3)!/5!3! =56

dimension of rectangle with ends of diagonal being(8,10) and (4,6) = 4*4

thus number of paths from (4,6) to (8,10) = (4+4)!/4!4! =70

so total number of paths from (1,1) to (8,10) via (4,6) = 56*70 =3920

1.7250

2.6350

3.7000

4.6000

Ratio of their interest at the end of a year = 3*6 : 4*5 : 5*4 = 18 : 20:20

As per question 20x -18x = 250

2x = 250

X = 125

So total interest = (18+20+20)*x = 58*125 = 7250

1. 32

2. 38

3. 43

4. 45

As per question a+b+c + (d+e+f) + g =256—————-1)

From figure , a+b+c + 2(d+e+f) + 3g = 132+144+123 = 399 ———-2)

Also g+e = 58 ———x)

f+g = 25—————y)

and d+g = 63————z)

adding all three , d+e+f + 3g = 58+25 + 63 = 146 ————-3)

from eq 2) and 3) , a+b+c + d+e+f = 399 – 146

a+b+c + d+e+f = 253————4)

from eq 1 and eq 4) g = 256 – 253 =3

so from eq x) , y) and z) d= 60, e = 55 and f = 22

Number of people playing tennis = 123

So g + f + e + c = 123

3+22 + 55 + c = 123

Or c = 43

the number of members who can play only tennis = 43

given eq of straight line is 3x + 5y – 45 = 0,

the line cuts x axis at

Put y = 0, 3x – 45 = 0 or x = 15 , so (15, 0)

Put x = 0, 5y – 45= 0 ,or y = 9

Thus the line cut y –axis at (0,9)

Thus we can say OAB is the triangle T which is right angled triangle so AB will be dia of triangle.

Diameter AB = (9^2 + 15^2)^1/2 = (81+225)^1/2 = (306)^1/2 = 17.54 (approx)

So radius = 17.54/2 = 9 (approx)

Let a man can finish the job alone in M days.

Given two machines can finish the job in 13 days so one machine can finish the job in 13*2 = 26 days

As given that Three men and eight machines can finish a job in half the time taken by three machines and eight men to finish the same job

So 3/M + 8/26 = 2(8/M + 3/26)

3/M + 4/13 = 16/M + 3/26

16/M – 3/M = 4/13 – 3/13

13/M = 1/13

M = 169

**Verbal Ability : | Q.01- Q.05 | Q.06- Q.10 | Q.11- Q.15 | Q.16- Q.20 | Q.21- Q.24 | Q.25- Q.29 | Q.30 – Q.34 |**

**Logical Reasoning : | Q.01- Q.04 | Q.05- Q.08 | Q.09- Q.12 | Q.13- Q.16 | Q.17- Q.20 | Q.21- Q.24 | Q.25 – Q.28 | Q.29 – Q.32 |**

**Quantitative Aptitude: | Q.01- Q.05 | Q.06- Q.10 | Q.11- Q.15 | Q.16- Q.20 | Q.21- Q.25 | Q.26- Q.30 | Q.31 – Q.34 |**

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