Two alcohol solutions, A and B, are mixed in the proportion - Quantitative Aptitude - Mixture
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The question below is from previous year CAT question from CAT 2020 exam comes from CAT Mixture: Two alcohol solutions, A and B, are mixed in the proportion
Find out by answering this question which tests an aspirant’s Quantitative Ability Skills.
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CAT 2020 - Slot 3 - Quantitative Aptitude - Mixture - Question 18 - Two alcohol solutions, A and B, are mixed in the proportion
Q. 18: Two alcohol solutions, A and B, are mixed in the proportion 1:3 by volume. The volume of the mixture is then doubled by adding solution A such that the resulting mixture has 72% alcohol. If solution A has 60% alcohol, then the percentage of alcohol in solution B is
1. 94%
2. 92%
3. 90%
4. 89%
18. B.
We are told that the A and B are mixed in the ratio 1:3
That means, one unit of A is mixed with 3 units of B
Observe that the total Volume is 1 + 3 = 4 units.
The volume is doubled by adding A, this implies that a quantity of 4 units of A is added to the existing 4units of the mixture.
The total volume will now be 4 + 4 = 8 units.
Of which three units are B and the rest 5 units are A. Hence the ratio of A to B in the final mixture is 5 : 3
We are told that A has a concentration of 60% alcohol and the final mixture has a concentration of 72% alcohol
300 + 3 × Concentration of B = 576
3 × Concentration of B = 576 – 300 = 276
3 × Concentration of B = 276 = 270 + 6
3 × Concentration of B = 270 + 6
Concentration of B = 270/3 + 6/3
Concentration of B = 90 + 2 = 92.
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