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Q. 1: If log(base12) 81=p then 3 { (4-p)/(4+p)} is equal to
1. log (base2) 8
2. log (base4) 16
3. log (base6) 8
4. log (base6) 16
Given , log(base12) 81 = p
4 log (base12) 3 = p
So 3 (4-p)/(4+p) = 3 (1- log(base12) 3 )/(1+ log(base12) 3)=3 × log(base12)(12/3)/log(base12)(12×3) = 3×log(base36) 4 = log(base6) 8
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