 # Let f(x) = min{2x^2,52−5x} | Quantitative Aptitude - Algebra – Functions

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The question below is from previous year CAT question from CAT 2018 exam comes from CAT Function: Let f(x) = min{2x^2,52−5x}. Find out by answering this question which tests an aspirant’s Quantitative Ability Skills:

## CAT 2018 - Slot-1 - Function - Question-1 - Let f(x) = min{2x^2,52−5x}

Q. 1: Let f(x) = min{2×2,52−5x}, where x is any positive real number. Then the maximum possible value of f(x) is

for maximum possible value , 2×2= 52−5x

2×2+ 5x – 52 = 0

(x -4)*(x+6.5) = 0

So x = 4 ( as x is positive real number )

Maximum possible value of f(x) = 2×2= 52−5x = 32 Counselling Session
By IIM Mentor

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