Pipes and Cisterns – A tank is fitted with pipes
CAT Quantitative Aptitude – Arithmetic
CAT Quantitative Aptitude
CAT DILR
- Sequential Output Tracing (Input Output)
- Syllogism
- Critical Reasoning: Assumptions & Conclusions
- Relationships
- Cause & Effect
- Circular Arrangement
- Coding-Decoding
- Complex Arrangements
- Critical Reasoning: Course of Action
- Critical Path
- Direction and Word Puzzle
- Games And Tournaments
- Linear Arrangement
- Team Selection
- Venn Diagram
- Bar Graphs
- Data Sufficiency
- Line Graph
- Pie Chart
- Tables and Caselets
CAT Verbal Ability
CAT 2018 – The CAT QA section has grown increasingly difficult since 2015. In order to tackle the tougher CAT Level QA questions for the CAT Exam, it is important to understand the basics of CAT. To obtain a great CAT score, make use of MBAP Free Study material with detailed solutions and video explanations. Check out MBAP free Mock test to take these questions in a test format for free.
You may also find remaining question solution of CAT 2018, Slot-1 by searching the question in the search bar.
The question below is from previous year CAT question from CAT 2018 exam comes from CAT Arithmetic: Pipes and Cisterns – A tank is fitted with pipes . Find out by answering this question which tests an aspirant’s Quantitative Ability Skills:
CAT 2018 - Slot-1 - Arithmetic - Question-2 -Pipes and Cisterns – A tank is fitted with pipes
Q. 2: A tank is fitted with pipes, some filling it and the rest draining it. All filling pipes fill at the same rate, and all draining pipes drain at the same rate. The empty tank gets completely filled in 6 hours when 6 filling and 5 draining pipes are on, but this time becomes 60 hours when 5 filling and 6 draining pipes are on. In how many hours will the empty tank get completely filled when one draining and two filling pipes areon?
Let the rate of each filling pipes be ‘x lts/hr’ similarly, the rate of each draining pipes be ‘y lts/hr’. As per the first condition,
Capacity of tank = (6x-5y)×6. (i)
Similarly, from the second condition, Capacity of tank = (5x – 6y)×60 (ii)
On equating (i) and (ii), we get (6x – 5y) × 6 = (5x – 6y)×60
or, 6x – 5y = 50x – 60y or, 44x = 55y
or, 4x = 5y or, x = 1.25y
Therefore, the capacity of the tank = (6x – 5y) × 6 = (7.5y – 5y) × 6 = 15y lts Effective rate of 2 filling pipes and 1 draining pipe = (2x – y) = (2.5y – y) = 1.5y Hence, the required time = 15y/1.5y=10 hours.
Past Year Question Paper & Solutions
Reach Us
- B-19, Satyam Shopping Complex, M. G. Road, Ghatkopar (E)- 400077
- 9820257156 / 9769617665
- info@mbapindia.com
Study With Us
Free Material Area
primary Menu
Inspiring Education… Assuring Success!!
Ⓒ 2020 – All Rights Are Reserved