The base exchange rates (BER) of currencies A, B and C with respect to L is in the ratio 100 : 120 : 1. Also The buying exchange rates (BR) of each of A, B, and C with respect to L will be in the ratio = 95 : 114: 0.95 and corresponding selling rates (SR) will be 110, 132 and 1.1 respectively as it is 10% more than base exchange rates.
The given information can be tabulated as follows:

From point 4) The outlet received 88,000 units of L by selling A.
From point 2) & 3) the ratio of amounts of L used to by A and B are in the ratio 5 : 3 and from the sales of A and B are in the ratio 5 : 9.
Let the base exchange rates for A, B and C 100x,120x and x .
Units sold of A = 88,000/110x = 800/x.
As the net addition is 800, the units of A bought is 800 + 800/x
Amount of L used in buying 800 + 800/x units is (800 +800/x)×0.95 × 100x = 76000(x+1) .
Now As the amount used to buy A and B are in the ratio 5 : 3,
The amount used to buy B is 76000(x+1) /5 X 3 = 45,600(x+1)
Number of units of B bought = 45,600(x+1)/114x = 400(x+1)/x
As the net addition of B is zero, number of units of B sold = 400(x+1)/x
The amount received = 400((x+1))/x×132x=52800(x+1)
The amount received form selling A = 88,000
As given 88,000 : 52800(x+1) = 5 : 9
880/528(x+1) = 5/9
(x+1) = 880*9/558*5 = 3
x = 2
1. The units of A bought is 800 + 800/x = 800+ 800/2 = 1200
2. As the net addition in the number of units of C is 3,000 and the buying and selling rates are in the ratio 0.95 and 1.1, assuming x units are sold 0.95 (x + 3000) = 1.1 (x) 0.15x = 2850 X= 19000
Answer: 1900
3. The base exchange rate of currency B with respect to L is 120x = 120*2 = 240
4. The buying exchange rate of currency C with respect to L on that day was 0.95x = 1.9
Answer: 1.9