- Sequential Output Tracing (Input Output)
- Syllogism
- Critical Reasoning: Assumptions & Conclusions
- Relationships
- Cause & Effect
- Circular Arrangement
- Coding-Decoding
- Complex Arrangements
- Critical Reasoning: Course of Action
- Critical Path
- Direction and Word Puzzle
- Games And Tournaments
- Linear Arrangement
- Team Selection
- Venn Diagram
- Bar Graphs
- Data Sufficiency
- Line Graph
- Pie Chart
- Tables and Caselets

Q. 3: At their usual efficiency levels, A and B together finish a task in 12 days. If A had worked half as efficiently as she usually does, and B had worked thrice as efficiently as he usually does, the task would have been completed in 9 days. How many days would A take to finish the task if she works alone at her usual efficiency?

1. 18

2. 12

3. 36

4. 24

let usual efficiency of A = 2a and that of B = b

So total work = 12*(2a+b) = 24a+12b————1)

In 2nd case when efficiency of A is halved and efficiency of B get tripled , new efficiency of A = 2a/2 = a

New efficiency of B = b*3 =3b

Total work = 9(a+3b) = 9a+27b ——————-2)

From eq 1) and 2)

24a+12b = 9a + 27b

15a = 15b

Or a=b

So total work = 24a+12b = 24a+12a = 36a

Time taken by A alone to complete the work = 36a/2a = 18 days

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