Q. 1: In a six-digit number, the sixth, that is, the rightmost, digit is the sum of the first three digits, the fifth digit is the sum of first two digits, the third digit is equal to the first digit, the second digit is twice the first digit and the fourth digit is the sum of fifth and sixth digits. Then, the largest possible value of the fourth digit is
The smallest possible value of first digit = 1
So 3rd digit = 1, 2nd digit = 1*2 = 2
5th digit = 1+2= 3
6th digit = 1+2+1 =4
4th digit = 3+4 =7
When value of first digit = 2
So 3rd digit = 2, 2nd digit = 2*2 = 4
5th digit = 1+4= 5
6th digit = 2+2+4=8
4th digit = som of 5th and 6th digit = 5+8 =13 (not possible )
So required answer =7
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