Q.3. A shopkeeper sells two tables, each procured at cost price p, to Amal and Asim at a profit of 20% and at a loss of 20%, respectively. Amal sells his table to Bimal at a profit of 30%, while Asim sells his table to Barun at a loss of 30%. If the amounts paid by Bimal and Barun are x and y, respectively, then (x −y) / p equals
1. 1.2
2. 1
3. 0.50
4. 0.7
Let Cost price each table = p
For Amal:
Cost price = p + 20% of p = 6p/5
Selling price = 6p/5 + 30% of 6p/5 = 7.8p/5= 1.56p
For Asim:
Cost price = p – 20% of p = 0.8p
Selling price = 0.8 p – 30% of 0.8p = 0.56p
x-y/p = 1.56p-0.56p/p = 1
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