MBAP logo

Among 100 students, x1 have birthdays in January | Quantitative Aptitude - CAT Number Series

CAT 2020 – The CAT QA section has grown increasingly difficult since 2015. In order to tackle the tougher CAT Level QA questions for the CAT Exam, it is important to understand the basics of CAT. To obtain a great CAT score, make use of MBAP Free Study material with detailed solutions and video explanations. Check out MBAP free Mock test to take these questions in a test format for free. You may also find remaining question solution of CAT 2020, slot 1 by searching the question in the search bar. 

The question below is from previous year CAT question from CAT 2020 exam comes from CAT Number Series: 13. Among 100 students, x1 have birthdays in January, x2 have birthdays in February, and so on. If x0 = max(x1, x2, …, x12), then the smallest possible value of x0 is 

Find out by answering this question which tests an aspirant’s Quantitative Ability Skills

CAT 2020 - Slot 1 - Quantitative Aptitude - Number Series - Question 13 - Among 100 students, x1 have birthdays in January

Q.13: Among 100 students, x1 have birthdays in January, x2 have birthdays in February, and so on. 

If x0 = max(x1, x2, …, x12), then the smallest possible value of x0 is

1. 8
2. 10
3. 12
4. 9

Correct Answer: 9

x0 = 100 (If all 100 had their birthdays on January)

If x0 = 3 (Not possible, because all x1 ,…..x12 together will be only 36)

So x0 will be lesser when the numbers are as close as possible

100/12=8.5

So if we add 8 (12 times) = 96

So, need to have 8,8,8,8,8,8,8,8,9,9,9,9 (Adding these 12 we will get 100)

x0 = 9

Past Year Question Paper & Solutions

Counselling Session
By IIM Mentor

Reach Us

primary Menu

Inspiring Education… Assuring Success!!
Ⓒ 2020 – All Rights Are Reserved

Free Content !!!
Signup now to get the All recent CAT Exam Paper with Solution... Subscribe below with your Email ID
Free Content !!!
Signup now to get the All recent CAT Exam Paper with Solution... Subscribe below with your Email ID