Among 100 students, x1 have birthdays in January | Quantitative Aptitude - CAT Number Series
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The question below is from previous year CAT question from CAT 2020 exam comes from CAT Number Series: 13. Among 100 students, x1 have birthdays in January, x2 have birthdays in February, and so on. If x0 = max(x1, x2, …, x12), then the smallest possible value of x0 is
Find out by answering this question which tests an aspirant’s Quantitative Ability Skills
CAT 2020 - Slot 1 - Quantitative Aptitude - Number Series - Question 13 - Among 100 students, x1 have birthdays in January
Q.13: Among 100 students, x1 have birthdays in January, x2 have birthdays in February, and so on.
If x0 = max(x1, x2, …, x12), then the smallest possible value of x0 is
1. 8
2. 10
3. 12
4. 9
Correct Answer: 9
x0 = 100 (If all 100 had their birthdays on January)
If x0 = 3 (Not possible, because all x1 ,…..x12 together will be only 36)
So x0 will be lesser when the numbers are as close as possible
100/12=8.5
So if we add 8 (12 times) = 96
So, need to have 8,8,8,8,8,8,8,8,9,9,9,9 (Adding these 12 we will get 100)
x0 = 9
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