Aron bought some pencils and sharpeners - CAT Quantitative Aptitude
CAT Quantitative Aptitude
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The question below is from previous year CAT question from CAT 2020 exam comes from CAT Quantitative Aptitude: Q.24. Aron bought some pencils and sharpeners. If the cost of one sharpener is 2 more than the cost of a pencil, then the minimum possible number of pencils bought by Aron and Aditya together is?
Find out by answering this question which tests an aspirant’s Quantitative Ability Skills
CAT 2020 - Slot 2 - Quantitative Aptitude - Question 24 - Aron bought some pencils and sharpeners
Q.24: Aron bought some pencils and sharpeners. Spending the same amount of money as Aron, Aditya bought twice as many pencils and 10 less sharpeners. If the cost of one sharpener is 2 more than the cost of a pencil, then the minimum possible number of pencils bought by Aron and Aditya together is
1. 33
2. 27
3. 30
4. 36
Correct Answer: 33 ( Option 1)
Pencils and it’s price = x | Sharpeners and it’s price = x+2 | |
Aron | p | s |
Aditya | 2p | s-10 |
(Aron) Px + sx + 2s = (Aditya) 2px + sx – 20 – 10x + 2s
Px = 10x + 20
x(p-10) = 20
Together they bought 3p pencils
Minimum value of p has to be 11
So, minimum pencils they bought together is 33
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