If x and y are positive real numbers satisfying - Quantitative Aptitude | CAT Number System |

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CAT 2020 – The CAT QA section has grown increasingly difficult since 2015. In order to tackle the tougher CAT Level QA questions for the CAT Exam, it is important to understand the basics of CAT. To obtain a great CAT score, make use of MBAP Free Study material with detailed solutions and video explanations. Check out MBAP free Mock test to take these questions in a test format for free.

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The question below is from previous year CAT question from CAT 2020 exam comes from sub-section CAT Number System: If x and y are positive real numbers satisfying.

Find out by answering this question which tests an aspirant’s Quantitative Ability Skills:

CAT 2020 – Slot 2 - CAT Number System - Question 7 - If x and y are positive real numbers satisfying

Question 7: If x and y are positive real numbers satisfying x + y = 102, then the minimum possible value of

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Answer:

Correct Answer: 2704

To find the minimum possible value keep x and y as close as possible

So, x = y = 51

= 2601(1 + 1/51)(1 + 1/51)

= 2601(52/51)( 52/51)

= 52 × 52

= 2704

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