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Let the m-th and n-th terms of the geometric - Quantitative Aptitude | CAT Progression |

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The question below is from previous year CAT question from CAT 2020 exam comes from sub-section CAT Progression: Let the m-th and n-th terms of the geometric. 

Find out by answering this question which tests an aspirant’s Quantitative Ability Skills:

CAT 2020 – Slot 2 - CAT Progression- Question 6 - Let the m-th and n-th terms of the geometric

Question 6: Let the m-th and n-th terms of a Geometric progression be 3/4  and 12, respectively, when m < n. If the common ratio of the progression is an integer r, then the smallest possible value of r + n – m is

1. -4
2. -2
3. 6
4. 2

Answer:

B.

3 /4   12

mth    nth

m > n

Given r is an integer, So rk = 12/(3/4) = 16

rk = 24 or 42

Since asked for minimum possible value, Taking rk = {(-2)}^2 or {(-4)}^2

k = n – m (From m how many terms we have to jump to reach n)

We have two cases r = – 2 and n – m = 4 —-> r + n – m = 2

r = – 4 and n – m = 2 —-> r + n – m = – 2

-2 is the smallest possible value

 

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