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Q. 22: Vimla starts for office every day at 9 am and reaches exactly on time if she drives at her usual speed of 40 km/hr. She is late by 6 minutes if she drives at 35 km/hr. One day, she covers two-thirds of her distance to office in one-thirds of her usual time to reach office, and then stops for 8 minutes. The speed, in km/hr, at which she should drive the remaining distance to reach office exactly on time is

2. 28

3. 29

4. 26

22. B.

Vimala’s speed has decreased from 40kmph to 35 kmph. That means her current speed is 35/40 of the original Speed. That means, her current speed is 7/8 th of the original speed. Therefore, the time taken will be 8/7 th of the original time taken.

Since she is 6 minutes late when travelling at 35kmph, 1/7th of the original time taken is 6 minutes.

Therefore the total time taken originally is 7 × 6 = 42 minutes.

1/3 rd of the original time taken = 42/3 = 14 minutes.

1/3 rd of the total distance is generally covered in 14 minutes.

Currently the same distance is to be covered in (42 – 14 – 8 = 20) minutes.

So, to reach the Destination on time, Vimala, must cover the same 1/3 rd of the Distance in 20 minutes instead of 14 minutes.

That means she has to 20/14 of the initial time.

Which is 10/7 of the original time

This implies that, in order to reach at the same point of time. The speed had to 7/10 or 70% of the original speed.

So, she has to travel at 70% of 40kmph = 28kmph.

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